Download the app

Questions  

 The ratio in which the plane r(i2j+3k)=17 divides the line joining the points 2i+4j+7k and  3i5j+8k is 

a
1:5
b
1:10
c
3:5
d
3:10

detailed solution

Correct option is D

Let the plane r→⋅(i→−2j→+3k→)=17 divide the line joining  the points −2i→+4→j˙+7k→ and 3i→−5j→+8k→ in the ratio t:1 at point PTherefore, point P is 3t−2t+1i→+−5t+4t+1j→+8t+7t+1k→This lies on the given plane∴ 3t−2t+1⋅(1)+−5t+4t+1(−2)+8t+7t+1(3)=17Solving, we gett=310

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The angle between the planes represented by 2x26y212z2+18yz+2zx+xy=0 is


phone icon
whats app icon