The ratio in which the plane r→⋅(i→−2j→+3k→)=17 divides the line joining the points −2i→+4j→+7k→ and  3i→−5j→+8k→ is

Let the plane r→⋅(i→−2j→+3k→)=17 divide the line joining  the points −2i→+4→j˙+7k→ and 3i→−5j→+8k→ in the ratio t:1 at point PTherefore, point P is 3t−2t+1i→+−5t+4t+1j→+8t+7t+1k→This lies on the given plane∴ 3t−2t+1⋅(1)+−5t+4t+1(−2)+8t+7t+1(3)=17Solving, we gett=310