A ray of light comes along the line Z = 0 and strikes the plane mirror kept along the plane P = 0 at B. A(2,1,6) is a point on the line Z=0 whose image about P=0 is, A'. It is given that L=0 is  x−23=y−14=z−65  and p= 0 is x+y-2z=3.The coordinates of A' areThe coordinates of B arelf  L1=0 is the reflected ray, then its equation is

Let Q(x2,y2,z2) be the image of A(2, 1, 6) about mirror x + y -22 - 3. Then, x2−21=y2−11=z2−6−2=−2(2+1−12−3)12+12+22=4⇒x2,y2,z2≡(6,5,−2)let  x−23=y−14=z−65=λx=2+3λ,y=1+4λ,z=6+5λ lies on plane x+y−2z=3⇒2+3λ+1+4λ−2(6+5λ)=3or  3+7λ−12−10λ=3 or −3λ=12 or λ=−4 Point B≡(−10,−15,−14) The equation of the reflected ray L1 =0 is the line joining Q(x2,y2, z2) and B(- 10, - 15, - 14). x+1016=y+1520=z+1412or  x+104=y+155=z+143