A ray of light is sent along the line x–2y–3=0. On reaching the line 3x–2y–5=0, the ray is reflected from it. The equation of the line containing the the reflected ray.

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29x−2y+31=0

29x+2y−31=0

29x−2y−31=0

29x+2y+31=0

answer is C.

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Detailed Solution

m1=12,m=−23,m2 is slope reflected line use m1−m1+mm1=m−m21+mm2

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