A ray of light travels along the line 2x−3y+5=0  and strikes a plane mirror lying along the line x+y=2 The equation of the straight line containing the reflected ray is

Let θ  be the angle which the ray  2x−3y+5 ⊨0makes with the line x+y=2  then  ⁡θ=2/3+11−2/3(1) =|5|=5  Reffected ray makes angle −θ  with x+y=2 so if the slopeof the reflected ray is m then m+11−m=tan⁡(−θ)=−5               ⇒ m=3/2. Also, the reflected ray passes through  (1/5,9/5) the point of intersection of the ray and the lineHence equation of the reflected ray is(y−9/5)=3/2(x−1/5)⇒3x−2y+3=0