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For a real number ‘y’, let [y] denote the integral part of ‘y’. Then derivative of the function $f (x) = \frac{T a n [x - π] π}{1 + {[x]}^{2}}$ is

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Correct option is A

[(x−π)]π is an integral multiple of πf(x)=0f′(x)=0

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For a real number ‘y’, let [y] denote the integral part of ‘y’. Then derivative of the function f(x)=Tanx−ππ1+x2 is

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Ready to Test Your Skills?

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For a real number ‘y’, let [y] denote the integral part of ‘y’. Then derivative of the function $f (x) = \frac{T a n [x - π] π}{1 + {[x]}^{2}}$ is