For real numbers x and y, we write xRy⇔x−y+2 is an irrational number. Then, the relation R is
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a
reflexive
b
Not symmetric
c
transitive
d
Not transitive
answer is A.
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Detailed Solution
xRy⇔x−y+2 is an irrational number. Let (x,x)∈RThen, x−x+2=2which is an irrational number∴ xR×,∀x∈RR is an reflexive relation. R is not symmetric since 2,1∈R since 2-1+2 is irrational but 1,2 ∉R since 1-2+2=1, which is rational R is not transitive because (1,3)∈R,since (1−3+2) is an irrational number and (3,2)∈R,since (3-2+2)=3 is an irrational number. but (1,2)∉R since (1−2+2)=1 is a rational number.∴R is not transitive relation.