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The real part of $z = \frac{1}{1 - \cos θ + i \sin θ}$ is

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11−cos⁡θ

12tan⁡θ

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Correct option is B

TIPIf z=1ω,then Re⁡(z)=Re⁡(ω)|ω|2∴ Re⁡(z)=1−cos⁡θ(1−cos⁡θ)2+sin2⁡θ=1−cos⁡θ1−2cos⁡θ+cos2⁡θ+sin2⁡θ=1−cos⁡θ2(1−cos⁡θ)=12

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The real part of z=11−cos⁡θ+isin⁡θ is

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The real part of $z = \frac{1}{1 - \cos θ + i \sin θ}$ is