The real solutions of the equation 2x+2⋅56−x=10x2 is/are

2x+2⋅56−x=2x2⋅5x2or  56−x−x2=2x2−x−2or  6−x−x2log10⁡5=x2−x−2log10⁡2( base 10) or  6−x−x21−log10⁡2=x2−x−2log10⁡2or  6−x−x2=log10⁡2x2−x−2−x2−x+6or  6−x−x2=log10⁡2[4−2x]or  x2+x−6=2log10⁡2(x−2)or  (x+3)(x−2)=log10⁡4(x−2)Therefore, either x=2 or x+3=log10⁡4⇒ x=log10⁡4−3=log10⁡41000⇒ x=−log10⁡(250)