The real value of m for which the substitution y=um will transform the differential equation 2x4ydydx+y4=4x6 into a homogeneous equation is
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a
0
b
1
c
2/3
d
3/2
answer is D.
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Detailed Solution
y=um⇒dydx=mum−1⋅dudx∴ Given equation ⇒2x4um⋅mum−1⋅dudx+u4m=4x6⇒dudx=4x6−u4m2mx4u2m−1For homogeneous equation degree should be same in numerator and denominator∴6=4m=4+2m−1 ⇒ m=3/2