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a
nπ+π4
b
nπ±π4
c
2nπ±π2
d
nπ+−1nπ4
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Correct option is C
1+icosθ1−2icosθ=1−2cos2θ+3icosθ1+4cos2θReal⇒cosθ=0⇒θ=2nπ±π2Similar Questions
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