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Questions  

 The real value of θ for which the expression 1+icosθ12icosθ is a real number, where i=1 , is 

a
nπ+π4
b
nπ±π4
c
2nπ±π2
d
nπ+−1nπ4

detailed solution

Correct option is C

1+icos⁡θ1−2icos⁡θ=1−2cos2⁡θ+3icos⁡θ1+4cos2⁡θReal⇒cos⁡θ=0⇒θ=2nπ±π2

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