A real valued function f(x) satisfies the functional equation f(x−y)=f(x)f(y)−f(a−x)f(a+y) for some given constant a and f(0)=1 , then f(2a−x) is equal to :
f(x)
−f(x)
f(−x)
f(a)+f(a−x)
f(x−y)=f(x)f(y)−f(a−x)f(a+y)
x=y=0 ⇒ f(0)=f(0)2−(f(a))2
⇒f(a)=0 as f(0)=1
f(2a−x)=f(a−(x−a))
=f(a)f(x−a)−f(a−a)f(a+x−a)
=−f(x)
∴ f(2a−x)=−f(x) .