First slide
Functions (XII)
Question

A real valued function f(x)  satisfies the functional equation f(xy)=f(x)f(y)f(ax)f(a+y)  for some given constant a  and f(0)=1 , then f(2ax)  is equal to :

Moderate
Solution

f(xy)=f(x)f(y)f(ax)f(a+y)

x=y=0f(0)=f(0)2(f(a))2

f(a)=0  as f(0)=1

f(2ax)=f(a(xa))

                    =f(a)f(xa)f(aa)f(a+xa)

                    =f(x)

f(2ax)=f(x) .

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App