First slide
Algebra of real valued functions
Question

A real valued function f(x) satisfies the functional equation f(xy)=f(x).f(y)f(ax)f(a+y)  for some given constant a and f(0) = 1  then f(2ax) =

Easy
Solution

Put x=y=0f(a)=0 

f(2ax)=f(a(xa))=f(a).f(xa)f(aa)fa+x-a=-fx

 

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