Q.

The real values of a for which the quadratic equation 2x2−a3+8a−1x+a2−4a=0 possesses roots of opposite signs are given by

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a

a>5

b

0

c

a>0

d

a>7

answer is B.

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Detailed Solution

The roots of the given equation will be of opposite signs if they are real and their product is negative. i.e. Discriminant ≥ 0 and Product of roots <0⇒ a3+8a−12−8a2−4a≥0 and a2-4a2<0⇒ a2−4a<0∵a2−4a<0⇒a3+8a−12−8a2−4a≥0⇒ 0
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