The real values of a for which the quadratic equation 2x2−a3+8a−1x+a2−4a=0 possesses roots of opposite signs are given by
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
a>5
b
0
c
a>0
d
a>7
answer is B.
(Unlock A.I Detailed Solution for FREE)
Detailed Solution
The roots of the given equation will be of opposite signs if they are real and their product is negative. i.e. Discriminant ≥ 0 and Product of roots <0⇒ a3+8a−12−8a2−4a≥0 and a2-4a2<0⇒ a2−4a<0∵a2−4a<0⇒a3+8a−12−8a2−4a≥0⇒ 0