The real values of x and y for which the  following equality hold, are respectively  x4+2xi−3x2+iy=(3−5i)+(1+2iy)

The given equality can be rewritten as x4−3x2+i(2x−y)=4+i(2y−5)⇒x4−3x2=4 and 2x−y=2y−5⇒x4−3x2−4=0 and 2x−3y+5=0⇒x2−4x2+1=0          ∵x2≠−1⇒x=±2∴ At x=2,y=3 and at x=−2,y=13