For real x , the function f(x) =(x−a)(x−b)(x−c) will be onto function provided
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a
a≥b≥c
b
a≤b≤c
c
a≤c≤b or a≥c≥b
d
None of these
answer is C.
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Detailed Solution
y=f(x) =(x−a)(x−b)(x−c) is onto ⇒ x2−(y+a+b)x+(ab+cy)=0 …(1) has real roots for all y∈R ⇒ (y+a+b)2−4(ab+cy)≥0 ∀ y∈R ⇒y2+2(a+b−2c)y+(a−b)2≥0 ∀y∈R ⇒ 4(a+b−2c)2+4(a−b)2≤0 ⇒(c−a)(c−b)≤0 ⇒ c lies between a and b ⇒ a≤c≤b or a≥c≥b .