First slide

Random variable and probability distribution

Question

The records of a hospital show that 10% of the cases of a certain disease are fatal. If 6 patients are suffering from
the disease, then the probability that only three will die is

Moderate

A

$1458 \times 10^{- 5}$
B

$1458 \times 10^{- 6}$
C

$41 \times 10^{- 6}$
D

$8748 \times 10^{- 5}$

Solution

$Probability of disease is fatal = p = 10 %$
$p = \frac{10}{100} = \frac{1}{10}, q = \frac{9}{10}$
Number of patients - 6, Number of die cases = 3
.'. Probability that 3 patients will die
$=^{6} C_{3} {(\frac{1}{10})}^{3} {(\frac{9}{10})}^{3} = 1458 \times 10^{- 5}$

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