A rectangle ABCD, where A≡(0,0),B≡(4,0), C≡(4,2),D≡(0,2), undergoes the following transformations successively:
i. f1(x,y)→(y,x)
ii. f2(x,y)→(x+3y,y)
iii. f3(x,y)→((x−y)/2,(x+y)/2)
The final figure will be
a square
a rhombus
a rectangle
a parallelogram
Clearly, A will remain as (0,0);f1 will make B as (0,4),f2 will make it (12,4) , and f3 will make it (4,8);f1 will
make C as (2,4),f2 will make it (14,4) , and f3 will make it (5,9) . Finally, f1 will make D as (2,0),f2 will make it (2,0) , and
f3 will make it (1,1) . So, we finally get A≡(0,0),B≡(4,8),C≡(5,9) , and D≡(1,1) . Hence,
mAB=84,mBC=9−85−4=1,mCD=9−15−1=84,mAD=1,mAC=95,mBD=8−14−1=73
Hence, the final figure will be a parallelogram.