Reflection of the point 1,1 with respect to the line 4x+3y−5=0 is α,β then α+β

If h,k is the image of the point x1,y1 with respect to the line ax+by+c=0  then  h−x1a=k−y1b=−2ax1+by1+ca2+b2Hence, if  α,β  is the image of the point 1,1 with respect to the line  4x+3y−5=0 then  α−14=β−13=−241+31−542+32Simplify α−14=β−13=−425 It implies α−14=−425α−1=−1625α=925and β−13=−425β−1=−1225β=1325Therefore, α+β=1325+925=2225