Reflection of the point 1,1 with respect to the line 4x+3y−5=0 is α,β then α+β

If (h,k) is the image of the point x1,y1 with respect to the line ax+by+c=0 then h−x1a=k−y1b=−2ax1+by1+ca2+b2 Hence, if (α,β) is the image of the point (1,1) with respect to the line 4x+3y−5=0 then α−14=β−13=−241+31−542+32Simplifyα−14=β−13=−425It implies α−14=−425α−1=−1625α=925Andβ−13=−425β−1=−1225β=1325 Therefore, α+β=1325+925=2225