The region represented by |z+a|+|z−a|<4a is
x2+y2<4a2
x2+y2>4a2
3x2−4y2<4a2
3x2+4y2<12a2
We have s(−a,0)s1(a,0)
⇒4ae=2a
⇒e=12
∴the locus of z=x+iy is x24a2+y23a2<1 ∵b2=4a2(1−14)
⇒3x2+4y2<12a2