A region in the $$x-y$$ plane is bounded by the curve $$y=25$$−$$x2$$ and the line y $$=0$$ If the point (a$$, $$a+$$ $$1) lies in the interior of the region then,

Correct option is 3a∈(−1,3)

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A region in the x-y plane is bounded by the curve $y = \sqrt{25 - x^{2}}$ and the line y =0 If the point (a, a+ 1) lies in the interior of the region then,

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a∈(−4,3)

a∈(−∞,−1)∈(3,∞)

a∈(−1,3)

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detailed solution

Correct option is C

y=25−x2 and y=0 bound the semicircle above the x-axis. Therefore,a+1>0…………(i)and a2+(a+1)2−25<0 or 2a2+2a−24<0or a2+a−12<0or −4

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A region in the x-y plane is bounded by the curve y=25−x2 and the line y =0 If the point (a, a+ 1) lies in the interior of the region then,

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A region in the x-y plane is bounded by the curve $y = \sqrt{25 - x^{2}}$ and the line y =0 If the point (a, a+ 1) lies in the interior of the region then,