First slide
Relations XII
Question

 The relation R={(a,b)/a,bZ and ax=b for some xZ} is 

Easy
Solution

a·1=a(a,a)R

Hence, R is reflexive

(a,0)R, but (0,a)R

Hence, R is not symmetric

(a,b),(b,c)R(a,c)R

Hence R is transitive

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