First slide

Relations XII

Question

The relation R defined in N as $aRb \Leftrightarrow b$ is divisible by a is

Easy

A

Reflexive but not symmetric
B

Symmetric but not transitive
C

Symmetric and transitive
D

None of these

Solution

For any $a \in N,$ we find that $a | a$ therefore R is reflexive but R is not transitive, because $aRb$ does not imply that $bRa$

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