Questions
A relation R on the set of complex numbers defined by
a
R is reflexive
b
R is symmetric
c
R is transitive
d
R is not equivalence
detailed solution
Correct option is D
Given z1,z2∈R⇔z1−z2z1+z2 is real number Clearly R is reflexive, because z1,z1∈R,Because z1−z1z1+z1=0 is a real number Clearly R is symmetric because z1,z2∈R⇔z2,z1∈RR is transitive also because z1,z2,z2,z3∈R ⇒z1,z3∈R Therefore, the relation is equivalence relation The correction option is fourth optionTalk to our academic expert!
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