The remainder when 20+21+22+23+……+22014 is divided by 9 is

Consider, 20+21+22+23+…….+22014=122015−12−1=22015−1 ∵ In G.P series Sn=arn−1r−1=2223671−1=4(9−1)671−1=4(9λ−1)−1,λ∈ℝ=4(9λ)−5=4(9λ)−9+4=9(4λ−1)+4Since it is divided by 9, then reminder is 4.Therefore, the correct answer is (3).