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The remainder when 9103 is divided by 25 is equal to

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answer is 4.

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Detailed Solution

We have, 9103=9×(81)51=9(80+1)51= 9(80)51+51C1(80)50+51C2(80)49+…+51C50(80)+1=9(25k+(51×80+1)}=25λ+36729=25λ+25×1469+4=25(λ+1469)+4Hence, the remainder is 4

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