Q.

The remainder when 2x5−3x4+5x3-3x2+7x−9  is divisible by  x2−x−3  is :

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a

33x + 4

b

41x + 3

c

41x + 44

d

33x−4

answer is B.

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Detailed Solution

132−35−37−902−11040006−33012   2−110 4     413  Remainder = 41x+3
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The remainder when 2x5−3x4+5x3-3x2+7x−9  is divisible by  x2−x−3  is :