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rf n is even, then the middle term in the expansion of ${(x^{2} + \frac{1}{x})}^{n}$ is 924 x⁶, then n is equal to

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Correct option is B

Since, n is even, therefore n2+1th term is the middle term.∴ Tn2+1=nCn/2x2n/21xn/2=924x6 (given)⇒ xn/2=x6⇒n=12

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rf n is even, then the middle term in the expansion of x2+1xnis 924 x6, then n is equal to

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rf n is even, then the middle term in the expansion of ${(x^{2} + \frac{1}{x})}^{n}$ is 924 x⁶, then n is equal to