In a right angled triangle the hypotenuse is 22 times the perpendicular drawn from the opposite vertex. Then theother acute angles of the triangle are

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π3

π8

3π8

π5

answer is B.

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Detailed Solution

P2sec2⁡θ+P2cosec2⁡θ=(22)2P2⇒ 1sin2⁡θcos2⁡θ=8⇒ sin2⁡2θ=122⇒ 2θ=π/4 or 3π/4⇒ θ=π/8,3π/8

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