The right hand limit of the function
f(x)=|x−4|x−4, x≠40, x=4
at x = 4, is
1
-1
0
non-existent
We have,
(RHL of f(x) at x=4 ) =limx→4+ f(x)=limh→0 f(4+h)=limh→0 |4+h−4|4+h−4=limh→0 |h|h=limh→0 hh=limh→0 1=1.