Rolle’s theorem can not applicable for
f(x)=1−x2 in [−1,1]
f(x)=|x| in [−1,1]
f(x)=x2−1 in [−1,1]
f(x)=x3+x2−x−1 in [−1,1]
f(x)=|x|⇒f'(x)=|x|x⇒f is not derivable at o∈(−1,1)