Rolle’s theorem holds for the functionx3+bx2+cx, 1≤x≤2 at the point43 , the value of b andc are
b=8, c=−5
b=−5, c=8
b=5, c=−8
b=−5, c=−8
Heref(1)=f(2) andf'(43)=0
⇒1+b+c=8+4b+2c and
3(43)2+2b(43)+c=0 16+8b+3c=0 7+3b+c=0 solving eqations (b,c)=(-5,8) .