First slide

Theorems of probability

Question

In a room there are 5 couples. Out of them if four persons are chosen at random, the probability that they are exactly two couples is

Easy

A

$\frac{1}{4}$
B

$\frac{1}{21}$
C

$\frac{1}{33}$
D

$\frac{3}{11}$

Solution

$n (S) = {}^{10}C_{4}$
$n (A) = {}^{5}C_{2}$
$P (A) = \frac{1}{21}$

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