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Q.

The roots of the equation   a(b−c) x2+b(c−a)x+c(a−b)=0 are

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a

c(a−b)a(b−c),b(c−a)c(a−b)

b

b(c−a)c(a−b),  1

c

1,c(a−b)a(b−c)

d

c(a−b)b(c−a),  1

answer is C.

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Detailed Solution

if a+b+c=0 then the roots are 1 and c/aSum of the Coefficients = a(b–c)+b(c–a)+c(a–b)=0∴ Roots are1,  c(a−b)a(b−c)
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