Q.
The roots of the equation a4+b4x2+4abcdx+c4+d4=0
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a
cannot be different, if real
b
are always real
c
are always imaginary
d
None of these
answer is A.
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Detailed Solution
The discriminant of the given equation isD=16a2b2c2d2−4a4+b4c4+d4=−4a4+b4c4+d4−4a2b2c2d2=−4a4c4+a4d4+b4c4+b4d4−4a2b2c2d2=−4a4c4+b4d4−2a2b2c2d2+a4d4+b4c4−2a2b2c2d2=−4a2c2−b2d22+a2d2−b2c22----1 If roots of the given equation are real, D≥0⇒−4a2c2−b2d22+a2d2−b2c22≥0⇒ a2c2−b2d22+a2d2−b2c22≤0⇒ a2c2−b2d22+a2d2−b2c22=0----2['.' Sum of two positive quantities cannot be negative] From (1) and (2), we get D = 0 Hence, the roots of the given quadratic equation are not different if they are real.
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