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Q.

The roots of the equation x2−x−6=x+2 are

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a

−2, 1, 4

b

0, 2, 4

c

0, 1, 4

d

-2, 2, 4

answer is D.

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Detailed Solution

x+2≥0⇒x≥−2Now, |(x+2)(x−3)|=x+2|x+2||x−3|=x+2⇒x+2=0 or |x−3|=1⇒x=−2,x=3±1 i.e., x=−2,2,4
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