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$S i n^{- 1} (\frac{x}{5}) + C o \sec^{- 1} (\frac{5}{4}) = \frac{π}{2}$ then $x =$

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Correct option is B

We know that sin-1ax+sin-1bx=π2⇒x=a2+b2 Given sin−1x5+cosec−154=π2 ⇒sin−1x5+sin−145=π2 ⇒5=x2+42 ⇒x=3

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Sin−1x5+Cosec−154=π2then x=

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$S i n^{- 1} (\frac{x}{5}) + C o \sec^{- 1} (\frac{5}{4}) = \frac{π}{2}$ then $x =$