s1,s2,s3.... s10 are the speakers in a conference. If s1 addresses only after s2 , then the number of ways the speakers addresses is
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a
10!
b
9!
c
10×8!
d
10!2
answer is D.
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Detailed Solution
The number of ways the speakers addresses is =10!2!(∵the order of s1&s2 is not considered ) (The number of permutations of ‘n’ different things where order of ‘r’ things is not to be considered is n!r!)