Sum of all three digit numbers (no digit being zero) having the property that all digits are perfect squares,
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answer is 13986.
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Detailed Solution
The non zero perfect square digits re 1,4, 91 can occur at units place 3⋅3=9 waysSum due to 1 at unit place is 1⋅9=9 waysSum due to 1 at tens place is 1⋅10⋅9=90 wayssum due to 1 at hundereds place 1⋅100⋅9=900 ways4 and 9 in a similar wayThus the sum of the desired number is 1+4+91+10+1009=13986