S:x2+y2−6x+4y−3=0 is a circle andL:4x+3y+19=0 is a straight line.

:Centre of S is (3, – 2)  and its radius is 32+(−2)2+3=4 Length of the perpendicular of (3, – 2) from the line L is 4(3)+3(−2)+19(4)2+(3)2=5  Which is greater yhen the radius ofS .So the line L lies outside the circle S