secθ=a2+b2a2−b2, where a,b,∈R, gives real values of θ if and only if
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a
a=b≠0
b
|a|≠|b|≠0
c
a+b=0,a≠0
d
none of these
answer is B.
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Detailed Solution
Clearly,a2+b2≥a2−b2 for all ||a|≠|b∣≠0,⇒ a2+b2a2−b2≥1 or. a2+b2a2−b2≤−1∴ secθ=a2+b2a2−b2 is meaningful.Thus, secθ=a2+b2a2−b2 gives real values of θ if and only |a|≠|b|≠0