sec–1(sin2x) is well-defined if and only if
x∈−12,12
x ∈ R
x∈(2n+1)π2:n∈Z
none of these
sec–1(sin2x) is well defined if and only ifsin2x ≥ 1 ⇔ sin2x = 1 (∴ sin2x >/ 1)∴x=nπ+π2,n∈Z