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Q.

secA+tanA=3⇒secA=

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a

1.66

b

2.77

c

1.65

d

1.60

answer is A.

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Detailed Solution

(sec2A−Tan2A)=1 ⇒secA-tanAsecA+tanA=1 secA-tanA=1secA+tanA=13 ⇒secA=53
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