Segment of the tangent to the curve xy=c2 at the points (x',y')which is contained between the co-ordinate axes, is bisected at the point:
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a
(−x',−y')
b
(y',x')
c
(x'/2,y'/2)
d
None
answer is D.
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Detailed Solution
[dydx](x',y')=−c2x'2=−y'x' ∴ Equation of tangent at (x',y') isy−y'=(−y'/x')(x−x')Which meets the co-ordinates axes at Aand B(say).Then A=(2x',0),B=(0,2y').Mid-point of AB=(x',y').