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Q.

The set of all real numbers x  for which x2−|x+2|+x>0 is

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a

(−∞,−2)

b

(−∞,−2)∪(2,∞)

c

(−∞,−1)∪(1,∞)

d

(2,∞)

answer is B.

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Detailed Solution

Case I: x+2≥0 or x≥−2∴ x2−2>0⇒ (x−2)(x+2)>0⇒ x<−2 or x>2∴ x∈[−2,−2)∪(2,∞)-----(1) Case II: x+2<0 or x<−2∴ x2+2x+2>0, which is true for real x . ∴ x∈(−∞,−2)----(2)From (1) and (2),x∈(−∞,−2)∪(2,∞)
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The set of all real numbers x  for which x2−|x+2|+x>0 is