First slide
Maxima and minima
Question

The set of all real values of λ for which the function 

f(x)=1-cos2x·(λ+sinx),x-π2,π2, has exactly one maxima and exactly one minima, is:

Moderate
Solution

f(x)=1-Cos2x(λ+sinx)  =Sin2x(λ+sinx)f1(x)=sin2xCosx+(λ+sinx)2sinxcosx=sinxcosx(2λ+3sinx)

For maximum or minimum,

f1(x)=0  sinx=0 or sinx=-2λ3 As there is exactly one max. and exactly one min, f'(x)=0 has exactly 2 roots -1<2λ3<1 and -2λ30  λ-32,32-{0}

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