First slide
Operations on Sets
Question

 Set of all values of x satisfying the equation |x+1|=5|x4| is 

Moderate
Solution

|x+1|=5|x4| |x+1|+|x4|=5 |x+1|+|x4|=|(x+1)+(4x)|    since x+y=x+y    happens if both x and y are positive or negative i.e xy0 (x+1)(4x)0 (x+1)(x4)0 x[1,4]

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