Q.

Set A and B have 3 and 6 elements respectively. What can be the minimum number of elements in A∪B

Easy

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answer is B.

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Detailed Solution

n(A∪B)=n(A)+n(B)-n(A∩B)=3+6-n(A∩B)Since, maximum number of elements in A∩B=3∴Minimum number of elements in A∪B=9-3=6.

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