Q.

A set contains 2n+1 elements. The number of subsets of this set containing more than n elements is equal to

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a

2n-1

b

2n

c

2n+1

d

22n

answer is D.

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Detailed Solution

Let the original set contains 2n+1 elements, then subsets of this set containing more than n elements, i.e., subsets containing n+1 elements, (n+2) elements, ....2n+1 elements.∴Required number of subsets=Cn+1   2n+1+Cn+2   2n+1+...+C2n   2n+1+C2n+1   2n+1=Cn   2n+1+Cn-1   2n+1+...+C1   2n+1+C0   2n+1=C0   2n+1+C1   2n+1+C2   2n+1+...+Cn-1   2n+1+Cn   2n+1=12[(1+1)2n+1] =1222n+1=22n.
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