First slide

Introduction to sets

Question

$A set A has 3 elements and another set B has 6 elements. then$

Moderate

A

$3 \leq n (A \cup B) \leq 6$
B

$3 \leq n (A \cup B) \leq 9$
C

$6 \leq n (A \cup B) \leq 9$
D

$0 \leq n (A \cup B) \leq 9$

Solution

$\begin{array}{l} we have \\ \min n (A \cup B) = \max {n (A), n (B)} = \max {3, 6} = 6 \\ Max n (A \cup B) = n (A) + n (B) = 9 \\ ∴ 6 \leq n (A \cup B) \leq 9 \end{array}$

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